Path: news.eternal-september.org!eternal-september.org!.POSTED!not-for-mail From: olcott Newsgroups: comp.theory Subject: =?UTF-8?Q?Re=3A_Analysis_of_Flibble=E2=80=99s_Latest=3A_Detecting_v?= =?UTF-8?Q?s=2E_Simulating_Infinite_Recursion_ZFC?= Date: Wed, 21 May 2025 17:34:39 -0500 Organization: A noiseless patient Spider Lines: 73 Message-ID: <100lkdv$32ib3$1@dont-email.me> References: <95db078e80b2868ed15a9a9a2af0280d96234a3a@i2pn2.org> <100jo18$2mhfd$1@dont-email.me> <100jpv9$2m0ln$4@dont-email.me> <100kt0c$2tae8$3@dont-email.me> <100ktr7$2reaa$1@dont-email.me> <100l09v$2tae8$5@dont-email.me> <100l1ov$2ul3j$1@dont-email.me> <100l3jh$2v0e9$1@dont-email.me> <100l5c8$2ul3j$2@dont-email.me> <100l75g$2vpq3$1@dont-email.me> <100l887$2ul3i$2@dont-email.me> <100l9gh$30aak$1@dont-email.me> <100lc4o$30pgm$1@dont-email.me> <100ld1u$312c9$1@dont-email.me> <100lg4g$31jt3$1@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Thu, 22 May 2025 00:34:40 +0200 (CEST) Injection-Info: dont-email.me; posting-host="1445173336acf9f867010d2c7ad38e9f"; logging-data="3230051"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+khVctGxhseWGmAmKON7VG" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:lHsKhtnrxnQj8gXyYkyHNMCIrB0= In-Reply-To: <100lg4g$31jt3$1@dont-email.me> X-Antivirus-Status: Clean Content-Language: en-US X-Antivirus: Norton (VPS 250521-10, 5/21/2025), Outbound message On 5/21/2025 4:21 PM, Richard Heathfield wrote: > On 21/05/2025 21:28, olcott wrote: >> On 5/21/2025 3:13 PM, Richard Heathfield wrote: >>> On 21/05/2025 20:28, olcott wrote: > > > >>>> I have only been talking about the ACTUAL >>>> conventional proof of the halting problem. >>> >>> The ACTUAL conventional proof of the Halting Problem goes something >>> like this: >>> >>> 1) assume that it is possible to devise an algorithm that can >>> determine in finitely many steps ascertain whether an arbitrary >>> program applied to arbitrary data does or does not stop. >>> >>> 2) given such an algorithm, imagine incorporating it into a program >>> that ascertains whether a supplied program with supplied data halts, >>> loops if it does, and halts if it doesn't. >>> >> >> This step is impossible. > > Correct. We have derived an impossible consequence of our assumption, > thus proving that the assumption is false. > >> It only seemed possible > > No. It never seemed possible. It always seemed like the impossible > contradiction that it is. > >> because no one ever >> tried to completely encode every detail. > > Why would they? One would have to be pretty stupid to try. > >> This screwy mistake came about > > It's not screwy, and it's not a mistake. It's a proof that there is at > least one thing which we'd like a computer to be able to do but which it > will never be able to do. > > Like you said, it's impossible. QED. > > >> because fools thought >> that a halt decider H is supposed to report on the behavior >> of the program that itself is contained within rather >> than the behavior that its actual input actually specifies. > > What your halt decider reports on is entirely up to you, but thanks to > Turing we know that it will not be able to act as a /universal/ > termination analyser that always gets the answer right regardless of the > input. > > Sometimes? Sure. bool decide(whatever){return true;} will get it right > sometimes. But for some inputs your decider will get it wrong. > >> int main() >> { >>    DDD(); // No HHH can report on the behavior of its caller. >> } > Show an actual input to HHH that actually does the opposite of whatever value that HHH returns. -- Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius hits a target no one else can see." Arthur Schopenhauer