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From: Richard Damon
Newsgroups: comp.theory
Subject: Re: DDD simulated by HHH cannot possibly halt (Halting Problem)
Date: Sun, 13 Apr 2025 19:12:42 -0400
Organization: i2pn2 (i2pn.org)
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In-Reply-To:
On 4/13/25 4:54 PM, olcott wrote:
> On 4/13/2025 3:46 PM, Fred. Zwarts wrote:
>> Op 13.apr.2025 om 21:59 schreef olcott:
>>> On 4/13/2025 3:54 AM, joes wrote:
>>>> Am Fri, 11 Apr 2025 10:56:32 -0500 schrieb olcott:
>>>>> On 4/11/2025 3:24 AM, Richard Heathfield wrote:
>>>>>> On 11/04/2025 08:57, Mikko wrote:
>>>>
>>>>>>> No proof of this principle has been shown so its use is not valid.
>>>>>>
>>>>>> No proof of Peano's axioms or Euclid's fifth postulate has been
>>>>>> shown.
>>>>>> That doesn't mean we can't use them.
>>>>>> Mr Olcott can have his principle if he likes, but only by EITHER
>>>>>> proving it (which, as you say, he has not yet done) OR by taking
>>>>>> it as
>>>>>> axiomatic, leaving the world of mainstream computer science behind
>>>>>> him,
>>>>>> constructing his own computational 'geometry' so to speak, and
>>>>>> abandoning any claim to having overturned the Halting Problem. Navel
>>>>>> contemplation beckons.
>>>>>> Axioms are all very well, and he's free to invent as many as he
>>>>>> wishes,
>>>>>> but nobody else is obliged to accept them.
>>>>>>
>>>>> *Simulating termination analyzer Principle*
>>>>> It is always correct for any simulating termination analyzer to stop
>>>>> simulating and reject any input that would otherwise prevent its own
>>>>> termination.
>>>> Sure. Why doesn’t the STA simulate itself rejecting its input?
>>>>
>>>
>>> Because that is a STUPID idea and categorically impossible
>>> because the outermost HHH sees its needs to stop simulating
>>> before any inner HHH can possibly see this.
>>>
>>
>> No, the outermost HHH does not see that. The programmer only dreamed
>> that it needs to stop.
>
> Empirically proven, nitwit.
Nope, just shows that the programmer was a nitwit, as you have actually
also proved that the input does halt, and thus that you "logic" is just
filled with contradictions because of your errors in definitions and
assumptions.
>
>> The outermost HHH aborts before it can see that no abort is needed,
>> because the innermost HHH would abort.
>
>