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Subject: Re: Incorrect mathematical integration
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From: Richard Hachel <r.hachel@wanadou.fr>
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Le 24/07/2024 à 14:47, "Paul.B.Andersen" a écrit :

> If the proton is passing a point in the ring with the speed v
> relative to the point, then the point in the ring is passing
> the proton a the speed v relative to the proton.

This is the only interesting sentence in your post.
The rest is just nonsense or tautology.

Indeed, if the proton passes at Vo=0.999991 c (for example) at a point A 
of the device, then the laws of physics state that point A passes at 
Vo=0.999991c.
If we transpose into real speed Vr, we have:
Vr=Vo/sqrt(1-Vo²/c)=235.7c


Likewise, this real speed is reciprocal.

In the proton frame, it is point A which passes near it at Vr=235.7c.

Now what does the global ring look like in the proton frame of reference, 
and above all what is the trajectory of point A during one revolution?

This is a good relativistic physics question.

Have fun answering this question...

I hope you have a lot of fun.

R.H.