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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.math
Subject: Re: how
Date: Fri, 26 Apr 2024 10:49:47 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <v0geub$2a19r$3@i2pn2.org>
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On 4/26/24 10:41 AM, WM wrote:
> Le 26/04/2024 à 04:03, Richard Damon a écrit :
> 
>>> If ω is existing, then something is next.
>>
>> next above, yes, ω+1
>>
>> next below, no,
> 
> I disagree.

Which makes you wrong.

> 
>> the problem is the set below it is unbounded,
> 
> The set is bounded by ω.

But ω isn't in the set, so it can't be the upper bound of the set that 
is below ω

Your logic just said that ω is the number before ω, so got stuck in a 
infinite loop.

After all, if the number below ω is the upper bound of the set of 
Natural Numbers, and that is itself ω, then the number below ω must be ω 
by your logic.

BOOM.

> 
>> and thus doesn't have a "highest" value in it.
> 
> The value is there but invisible.
> 

Nope. No such thing.

> Regards, WM
> 
>