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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: H(D,D) cannot even be asked about the behavior of D(D) V3
 ---IGNORING ALL OTHER REPLIES
Date: Mon, 17 Jun 2024 08:03:56 -0500
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On 6/17/2024 2:20 AM, Mikko wrote:
> On 2024-06-16 12:47:09 +0000, olcott said:
> 
>> On 6/16/2024 2:53 AM, Mikko wrote:
>>> On 2024-06-15 16:22:09 +0000, olcott said:
>>>
>>>> On 6/13/2024 8:24 PM, Richard Damon wrote:
>>>>  > On 6/13/24 11:32 AM, olcott wrote:
>>>>  >>
>>>>  >> It is contingent upon you to show the exact steps of how H computes
>>>>  >> the mapping from the x86 machine language finite string input to
>>>>  >> H(D,D) using the finite string transformation rules specified by
>>>>  >> the semantics of the x86 programming language that reaches the
>>>>  >> behavior of the directly executed D(D)
>>>>  >>
>>>>  >
>>>>  > Why? I don't claim it can.
>>>>
>>>> The first six steps of this mapping are when instructions
>>>> at the machine address range of [00000cfc] to [00000d06]
>>>> are simulated/executed.
>>>>
>>>> After that the behavior of D correctly simulated by H diverges
>>>> from the behavior of D(D) because the call to H(D,D) by D
>>>> correctly simulated by H cannot possibly return to D.
>>>>
>>>> _D()
>>>> [00000cfc](01) 55          push ebp
>>>> [00000cfd](02) 8bec        mov ebp,esp
>>>> [00000cff](03) 8b4508      mov eax,[ebp+08]
>>>> [00000d02](01) 50          push eax       ; push D
>>>> [00000d03](03) 8b4d08      mov ecx,[ebp+08]
>>>> [00000d06](01) 51          push ecx       ; push D
>>>> [00000d07](05) e800feffff  call 00000b0c  ; call H
>>>> [00000d0c](03) 83c408      add esp,+08
>>>> [00000d0f](02) 85c0        test eax,eax
>>>> [00000d11](02) 7404        jz 00000d17
>>>> [00000d13](02) 33c0        xor eax,eax
>>>> [00000d15](02) eb05        jmp 00000d1c
>>>> [00000d17](05) b801000000  mov eax,00000001
>>>> [00000d1c](01) 5d          pop ebp
>>>> [00000d1d](01) c3          ret
>>>> Size in bytes:(0034) [00000d1d]
>>>
>>> When you put "V2" or "V3" or something similar on the subject line
>>> you should tell what is different from the original version.
>>>
>>
>> I ask what are the steps
>> I provide 6 steps and then ask what are the next steps.
>> I provide all of the steps.
> 
> In which version?
> 

*This is the simplest possible version*

void DDD()
{
   H0(DDD);
}

After six steps of DDD are correctly emulated by H0
what machine address of DDD would it be at?

_DDD()
[00001fd2] 55               push ebp      ; housekeeping
[00001fd3] 8bec             mov ebp,esp   ; housekeeping
[00001fd5] 68d21f0000       push 00001fd2 ; push DDD
[00001fda] e8f3f9ffff       call 000019d2 ; call H0
[00001fdf] 83c404           add esp,+04   ; housekeeping
[00001fe2] 5d               pop ebp       ; housekeeping
[00001fe3] c3               ret           ; return to caller
Size in bytes:(0018) [00001fe3]



-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer