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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Liar detector: Fred, Richard, Joes and Alan --- Honest Dialogue ?
Date: Sat, 20 Jul 2024 08:28:36 -0500
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On 7/20/2024 3:54 AM, Mikko wrote:
> On 2024-07-19 14:39:25 +0000, olcott said:
> 
>> On 7/19/2024 3:51 AM, Mikko wrote:
>>> On 2024-07-18 13:17:22 +0000, olcott said:
>>>
>>>> On 7/18/2024 2:40 AM, Mikko wrote:
>>>>> On 2024-07-17 13:00:55 +0000, olcott said:
>>>>>
>>>>>> On 7/17/2024 1:43 AM, Mikko wrote:
>>>>>>> On 2024-07-16 14:21:28 +0000, olcott said:
>>>>>>>>
>>>>>>>> When simulated input DDD stops running {if and only if}
>>>>>>>> the simulation of this input DDD has been aborted this
>>>>>>>> necessitates that input DDD specifies non-halting behavior
>>>>>>>
>>>>>>> DDD does not stop runnig unless it is completely exeuted.
>>>>>>
>>>>>> _DDD()
>>>>>> [00002163] 55         push ebp      ; housekeeping
>>>>>> [00002164] 8bec       mov ebp,esp   ; housekeeping
>>>>>> [00002166] 6863210000 push 00002163 ; push DDD
>>>>>> [0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
>>>>>> [00002170] 83c404     add esp,+04
>>>>>> [00002173] 5d         pop ebp
>>>>>> [00002174] c3         ret
>>>>>> Size in bytes:(0018) [00002174]
>>>>>>
>>>>>> DDD emulated by HHH according to the semantic meaning of
>>>>>> its x86 instructions never stop running unless aborted.
>>>>>
>>>>> You mean HHH's simulation of DDD may not termite before HHH aborts it?
>>>>
>>>> When we examine the infinite set of every HHH/DDD pair such that:
>>>> HHH₁ one step of DDD₁ is correctly emulated by HHH₁.
>>>> HHH₂ two steps of DDD₂ are correctly emulated by HHH₂.
>>>> HHH₃ three steps of DDD₃ are correctly emulated by HHH₃.
>>>> ...
>>>> HHH∞ The emulation of DDD∞ by HHH∞ never stops running.
>>>>
>>>> When each DDD of the HHH/DDD pairs above is correctly emulated
>>>> by its corresponding HHH according to the semantic meaning of its
>>>> x86 instructions it CANNOT POSSIBLY reach past its own machine
>>>> address 0000216b, not even by an act of God.
>>>
>>> You apparently mean that no HHHᵢ can simulate the corresponding DDDᵢ to
>>> its termination?
>>
>> No I don't mean that at all that incorrectly allocates the error
>> to the emulator.
> 
> Anyway you did not say that some HHHᵢ can simulate the corresponding DDDᵢ
> to its termination. And each DDDᵢ does terminate, whether simulated or not.

*Until you quit lying about this we cannot have an honest dialog*

int main()
{
   DDD();
}

Calls HHH(DDD) that must abort the emulation of its input
or {HHH, emulated DDD and executed DDD} never stop running.



-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer