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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Any honest person that knows the x86 language can see... predict
 correctly is to say Halting,
Date: Thu, 1 Aug 2024 07:30:47 -0500
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On 8/1/2024 6:34 AM, Richard Damon wrote:
> On 7/31/24 11:51 PM, olcott wrote:
>> On 7/31/2024 10:08 PM, wij wrote:
>>> On Tue, 2024-07-30 at 18:50 -0500, olcott wrote:
>>>>
>>>> It is not supposed to be a general solution to the halting problem.
>>>> it only shows how the "impossible" input is correctly determined
>>>> to be non halting.
>>>>
>>>
>>> But how do you determine it is non-halting?
>>>
>>> As I know you are even unable to define what 'halt' mean !!!
>>>
>> I have done this thousands of times and after someone
>> has read these thousands of times they say that I never
>> said it once.
>>
>> void DDD()
>> {
>>    HHH(DDD);
>>    return;
>> }
>>
>> int main()
>> {
>>    HHH(DDD);
>> }
>>
>> If DDD correctly emulated by HHH cannot possibly
>> reach its return instruction then it never halts.
>>
>>
> 
> But only *IF*  HHH *DOES* correctly emulate its input, which means it 
> can't abort its emulation,

*No stupid it has never meant that*

<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
     *simulating halt decider H correctly simulates its input D*
     *until H correctly determines that its simulated D would never*
     *stop running unless aborted*
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer