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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,comp.ai.philosophy
Subject: Re: HHH(DDD) computes the mapping from its input to HHH emulating
 itself emulating DDD --- anyone that says otherwise is a liar
Date: Sun, 17 Nov 2024 20:35:43 -0600
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On 11/17/2024 8:26 PM, Richard Damon wrote:
> On 11/17/24 8:44 PM, olcott wrote:
>> On 11/17/2024 4:03 PM, Richard Damon wrote:
>>> On 11/17/24 3:49 PM, olcott wrote:
>>>> On 11/17/2024 1:56 PM, Richard Damon wrote:
>>>>> On 11/17/24 1:36 PM, olcott wrote:
>>>>>> void DDD()
>>>>>> {
>>>>>>    HHH(DDD);
>>>>>>    return;
>>>>>> }
>>>>>>
>>>>>> _DDD()
>>>>>> [00002172] 55         push ebp      ; housekeeping
>>>>>> [00002173] 8bec       mov ebp,esp   ; housekeeping
>>>>>> [00002175] 6872210000 push 00002172 ; push DDD
>>>>>> [0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
>>>>>> [0000217f] 83c404     add esp,+04
>>>>>> [00002182] 5d         pop ebp
>>>>>> [00002183] c3         ret
>>>>>> Size in bytes:(0018) [00002183]
>>>>>>
>>>>>> DDD emulated by any encoding of HHH that emulates N
>>>>>> to infinity number of steps of DDD cannot possibly
>>>>>> reach its "return" instruction final halt state.
>>>>>>
>>>>>
>>>>> Except your DDD *CAN'T BE EMULTATED* by *ANY* HHH, as it is 
>>>>> IMPOSSIBLE to emulate the Call HHH per the x86 language from your 
>>>>> input, as the data isn't tnere.
>>>>>
>>>>
>>>> In patent law this is called incorporation by reference.
>>>
>>> And you need to PRECISELY specify what you are referencing.
>>>
>>>
>>>> I referred to every element of an infinite set of encodings
>>>> of HHH. You already know that it is ridiculously stupid
>>>> that you suggest I should write them all down.
>>>
>>> And thus admit that you are not talking sense, as each HHH that you 
>>> think of creates a DIFFERENT program DDD
>>>
>>>>
>>>> When each of them correctly emulates N instructions of its
>>>> input then N instructions have been correctly emulated. It
>>>> is despicably dishonest of you to say that when N instructions
>>>> have been correctly emulated that no instructions have been
>>>> correctly emulating.
>>>
>>> No, it is dishonest for you to lie.
>>>
>>> I never said that N instructions correctly emulated is no 
>>> instructions correctly emulated, just that it isn't a correct 
>>> emulation that provides the answer for the semantic property of 
>>> halting, which requires emulating to the final state or an unbounded 
>>> number of steps.
>>>
>>
>> void Infinite_Recursion()
>> {
>>    Infinite_Recursion();
>>    return;
>> }
>>
>> You are stupid liar. A smart liar would not be caught
>> in a lie with such a simple counter-example
>> THAT IS NEITHER EMULATED TO THE FINAL STATE NOR AN
>> UNBOUNDED NUMBER OF STEPS TO DETERMINE NON-HALT STATUS.
>>
> 
> No, but it is the fact that it CAN be emulated for an unbounded number 
> of steps that makes it non-halting. 

Your rebuttals are stupid.
It cannot be emulated for an unbounded number of steps.
That is a stupid thing to say.

If you were not stupid you could say that it cannot possibly
reach its "return" instruction final halt state even in a
hypothetical number of steps.


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer