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Date: Thu, 23 Nov 2023 02:34:40 -0800 (PST)
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From: Richard Verret <rverret97@gmail.com>
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Le 21/11/2023 =C3=A0 19:52, Richard Verret a =C3=A9crit :
> Dans ma recherche je suis arriv=C3=A9 =C3=A0 un espace des vitesses F o=
=C3=B9 les =C3=A9l=C3=A9ments sont d=C3=A9finis par y =3D b f  avec b =3D a=
rgsh v/c =3D argth Vp/c, f =C3=A9tant le vecteur unitaire de la vitesse par=
 rapport =C3=A0 l=E2=80=99espace de r=C3=A9f=C3=A9rence.
Dans un espace perceptible S d=E2=80=99un observateur, un point Mp de vites=
se r=C3=A9elle v et de vitesse perceptible Vp, est d=C3=A9fini par l=E2=80=
=99angle =CE=B2 par rapport au r=C3=A9f=C3=A9rentiel de cet observateur tel=
 que: sin =CE=B2 =3D Vp/c, tg =CE=B2 =3D v/c, cos=CE=B2 =3D Vp/v. Le scalai=
re b s=E2=80=99=C3=A9crit donc: b =3D argsh tg=CE=B2 =3D argth Sin=CE=B2 qu=
i est une identit=C3=A9 math=C3=A9matique. Il suffit de d=C3=A9river par ra=
pport =C3=A0 =CE=B2 pour s=E2=80=99en rendre compte. J=E2=80=99ai =C3=A9t=
=C3=A9 tr=C3=A8s content d=E2=80=99arriver =C3=A0 cette relation math=C3=A9=
matique car elle confirmait les hypoth=C3=A8ses physiques que j=E2=80=99ava=
is faites.=20